36v^2-180v-56=0

Solution for 36v^2-180v-56=0 equation:

36v^2-180v-56=0

a = 36; b = -180; c = -56;
Δ = b2-4ac
Δ = -1802-4·36·(-56)
Δ = 40464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40464}=\sqrt{144*281}=\sqrt{144}*\sqrt{281}=12\sqrt{281}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-12\sqrt{281}}{2*36}=\frac{180-12\sqrt{281}}{72}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+12\sqrt{281}}{2*36}=\frac{180+12\sqrt{281}}{72}
$